Answer

First, we see that the center of this hyperbola is . Next, since the transverse axis is vertical, we need to add and subtract the value of a to the y--component of the center in order to calculate the vertices. Thus, the vertices are and . The foci are found in a similar fashion and are given by and . The eccentricity of this hyperbola is

Last but not least, the equations of the asymptotes are

and

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James A. Sellers